Mount Auburn, Indiana

From Wikipedia, the free encyclopedia

Mount Auburn is a town in Wayne County, Indiana, United States. The population was 75 at the 2000 census.

1 Geography
2 Demographics
3 Facts
4 External links

[edit] Geography

Mount Auburn is located at 39°48′46″N, 85°11′31″W (39.812879, -85.191863)^GR1.

According to the United States Census Bureau, the town has a total area of 0.6 km² (0.2 mi²). 0.6 km² (0.2 mi²) of it is land and 4.35% is water.

[edit] Demographics

As of the census^GR2 of 2000, there were 75 people, 31 households, and 23 families residing in the town. The population density was 131.6/km² (337.7/mi²). There were 34 housing units at an average density of 59.7/km² (153.1/mi²). The racial makeup of the town was 100.00% White.

There were 31 households out of which 29.0% had children under the age of 18 living with them, 74.2% were married couples living together, 3.2% had a female householder with no husband present, and 22.6% were non-families. 19.4% of all households were made up of individuals and 12.9% had someone living alone who was 65 years of age or older. The average household size was 2.42 and the average family size was 2.79.

In the town the population was spread out with 20.0% under the age of 18, 5.3% from 18 to 24, 32.0% from 25 to 44, 18.7% from 45 to 64, and 24.0% who were 65 years of age or older. The median age was 41 years. For every 100 females there were 108.3 males. For every 100 females age 18 and over, there were 100.0 males.

The median income for a household in the town was $30,313, and the median income for a family was $31,667. Males had a median income of $37,500 versus $28,125 for females. The per capita income for the town was $17,624. There were no families and 3.2% of the population living below the poverty line, including no under eighteens and none of those over 64.