Merrill, Iowa

From Wikipedia, the free encyclopedia

Merrill is a city in Plymouth County, Iowa, along the Floyd River. The population was 754 at the 2000 census.

[edit] Geography

Merrill is located at 42°43′17″N, 96°15′3″W (42.721461, -96.250779)^GR1.

According to the United States Census Bureau, the city has a total area of 1.1 km² (0.4 mi²), all land. It is located near the Floyd River, and is on US Highway 75 north of Sioux City.

[edit] Demographics

As of the census^GR2 of 2000, there were 754 people, 280 households, and 203 families residing in the city. The population density was 677.0/km² (1,739.5/mi²). There were 294 housing units at an average density of 264.0/km² (678.3/mi²). The racial makeup of the city was 98.41% White, 0.40% African American, 0.27% Asian, 0.66% from other races, and 0.27% from two or more races. Hispanic or Latino of any race were 1.46% of the population.

There were 280 households out of which 37.5% had children under the age of 18 living with them, 63.2% were married couples living together, 7.5% had a female householder with no husband present, and 27.5% were non-families. 24.3% of all households were made up of individuals and 12.9% had someone living alone who was 65 years of age or older. The average household size was 2.69 and the average family size was 3.24.

In the city the population was spread out with 31.2% under the age of 18, 5.7% from 18 to 24, 27.9% from 25 to 44, 17.8% from 45 to 64, and 17.5% who were 65 years of age or older. The median age was 36 years. For every 100 females there were 113.6 males. For every 100 females age 18 and over, there were 105.1 males.

The median income for a household in the city was $43,333, and the median income for a family was $50,000. Males had a median income of $31,620 versus $21,845 for females. The per capita income for the city was $15,656. About 2.1% of families and 4.1% of the population were below the poverty line, including 2.2% of those under age 18 and 5.1% of those age 65 or over.