Luxemburg, Iowa

From Wikipedia, the free encyclopedia

Luxemburg is a city in Dubuque County, Iowa, United States. It is part of the 'Dubuque, Iowa Metropolitan Statistical Area'. The population was 246 at the 2000 census.

[edit] Geography

Luxemburg is located at 42°36′17″N, 91°4′36″W (42.604830, -91.076542)^GR1.

According to the United States Census Bureau, the city has a total area of 1.2 km² (0.5 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 246 people, 92 households, and 72 families residing in the city. The population density was 206.5/km² (540.2/mi²). There were 94 housing units at an average density of 78.9/km² (206.4/mi²). The racial makeup of the city was 100.00% White.

There were 92 households out of which 31.5% had children under the age of 18 living with them, 70.7% were married couples living together, 4.3% had a female householder with no husband present, and 21.7% were non-families. 20.7% of all households were made up of individuals and 12.0% had someone living alone who was 65 years of age or older. The average household size was 2.67 and the average family size was 3.10.

In the city the population was spread out with 27.6% under the age of 18, 6.1% from 18 to 24, 27.2% from 25 to 44, 18.7% from 45 to 64, and 20.3% who were 65 years of age or older. The median age was 39 years. For every 100 females there were 100.0 males. For every 100 females age 18 and over, there were 100.0 males.

The median income for a household in the city was $35,833, and the median income for a family was $46,667. Males had a median income of $26,042 versus $19,643 for females. The per capita income for the city was $15,314. None of the population or families were below the poverty line.