Lowesville, North Carolina

From Wikipedia, the free encyclopedia

Lowesville is a census-designated place (CDP) in Lincoln County, North Carolina, United States. The population was 1,440 at the 2000 census.

[edit] Geography

Lowesville is located at 35°25′17″N, 81°0′9″W (35.421325, -81.002412)^GR1.

According to the United States Census Bureau, the CDP has a total area of 17.6 km² (6.8 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 1,440 people, 552 households, and 422 families residing in the CDP. The population density was 81.6/km² (211.4/mi²). There were 589 housing units at an average density of 33.4/km² (86.5/mi²). The racial makeup of the CDP was 92.29% White, 6.53% African American, 0.21% Native American, 0.83% Asian, and 0.14% from two or more races. Hispanic or Latino of any race were 1.60% of the population.

There were 552 households out of which 34.8% had children under the age of 18 living with them, 64.5% were married couples living together, 8.9% had a female householder with no husband present, and 23.4% were non-families. 19.7% of all households were made up of individuals and 8.2% had someone living alone who was 65 years of age or older. The average household size was 2.61 and the average family size was 2.99.

In the CDP the population was spread out with 24.3% under the age of 18, 7.5% from 18 to 24, 33.3% from 25 to 44, 25.3% from 45 to 64, and 9.6% who were 65 years of age or older. The median age was 36 years. For every 100 females there were 99.7 males. For every 100 females age 18 and over, there were 99.3 males.

The median income for a household in the CDP was $51,333, and the median income for a family was $53,000. Males had a median income of $36,316 versus $24,280 for females. The per capita income for the CDP was $28,072. About 5.9% of families and 7.3% of the population were below the poverty line, including 8.8% of those under age 18 and 10.7% of those age 65 or over.