Lineville, Iowa

From Wikipedia, the free encyclopedia

Lineville is a city in Wayne County, Iowa, United States. The population was 273 at the 2000 census.

[edit] Geography

Lineville is located at 40°35′7″N, 93°31′23″W (40.585289, -93.523177)^GR1.

According to the United States Census Bureau, the city has a total area of 2.4 km² (0.9 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 273 people, 126 households, and 75 families residing in the city. The population density was 115.8/km² (300.5/mi²). There were 150 housing units at an average density of 63.6/km² (165.1/mi²). The racial makeup of the city was 99.63% White and 0.37% Pacific Islander.

There were 126 households out of which 22.2% had children under the age of 18 living with them, 52.4% were married couples living together, 5.6% had a female householder with no husband present, and 39.7% were non-families. 36.5% of all households were made up of individuals and 23.8% had someone living alone who was 65 years of age or older. The average household size was 2.17 and the average family size was 2.82.

In the city the population was spread out with 22.3% under the age of 18, 4.8% from 18 to 24, 23.8% from 25 to 44, 17.2% from 45 to 64, and 31.9% who were 65 years of age or older. The median age was 44 years. For every 100 females there were 88.3 males. For every 100 females age 18 and over, there were 91.0 males.

The median income for a household in the city was $30,625, and the median income for a family was $35,357. Males had a median income of $31,094 versus $18,750 for females. The per capita income for the city was $18,414. About 18.1% of families and 24.0% of the population were below the poverty line, including 32.1% of those under the age of eighteen and 22.7% of those sixty five or over.