Liberty, Nebraska

From Wikipedia, the free encyclopedia

Liberty is a village in Gage County, Nebraska, United States. The population was 86 at the 2000 census.

[edit] Geography

Liberty is located at 40°5′6″N, 96°29′0″W (40.085028, -96.483336)^GR1.

According to the United States Census Bureau, the village has a total area of 0.6 km² (0.2 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 86 people, 34 households, and 24 families residing in the village. The population density was 132.8/km² (348.0/mi²). There were 39 housing units at an average density of 60.2/km² (157.8/mi²). The racial makeup of the village was 93.02% White, 3.49% Native American, 1.16% from other races, and 2.33% from two or more races. Hispanic or Latino of any race were 3.49% of the population.

There were 34 households out of which 32.4% had children under the age of 18 living with them, 58.8% were married couples living together, 8.8% had a female householder with no husband present, and 29.4% were non-families. 26.5% of all households were made up of individuals and 8.8% had someone living alone who was 65 years of age or older. The average household size was 2.53 and the average family size was 2.83.

In the village the population was spread out with 29.1% under the age of 18, 4.7% from 18 to 24, 24.4% from 25 to 44, 26.7% from 45 to 64, and 15.1% who were 65 years of age or older. The median age was 40 years. For every 100 females there were 95.5 males. For every 100 females age 18 and over, there were 90.6 males.

The median income for a household in the village was $18,750, and the median income for a family was $22,813. Males had a median income of $19,583 versus $16,250 for females. The per capita income for the village was $10,793. There were no families and 3.5% of the population living below the poverty line, including no under eighteens and 7.7% of those over 64.