Lebanon, South Dakota

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For other places with the same name, see Lebanon (disambiguation).

Lebanon is a town in Potter County, South Dakota, United States. The population was 86 at the 2000 census.

[edit] Geography

Lebanon is located at 45°4′12″N, 99°46′15″W (45.069875, -99.770730)^GR1.

According to the United States Census Bureau, the town has a total area of 1.4 km² (0.5 mi²), all land.

Lebanon has been assigned the ZIP code 57455 and the FIPS place code 36260.

[edit] Demographics

As of the census^GR2 of 2000, there were 86 people, 39 households, and 28 families residing in the town. The population density was 62.7/km² (160.8/mi²). There were 54 housing units at an average density of 39.3/km² (100.9/mi²). The racial makeup of the town was 98.84% White and 1.16% Native American.

There were 39 households out of which 28.2% had children under the age of 18 living with them, 59.0% were married couples living together, 12.8% had a female householder with no husband present, and 28.2% were non-families. 25.6% of all households were made up of individuals and 17.9% had someone living alone who was 65 years of age or older. The average household size was 2.21 and the average family size was 2.61.

In the town the population was spread out with 18.6% under the age of 18, 4.7% from 18 to 24, 14.0% from 25 to 44, 30.2% from 45 to 64, and 32.6% who were 65 years of age or older. The median age was 53 years. For every 100 females there were 104.8 males. For every 100 females age 18 and over, there were 89.2 males.

The median income for a household in the town was $25,625, and the median income for a family was $37,500. Males had a median income of $47,500 versus $18,750 for females. The per capita income for the town was $16,135. There were 13.6% of families and 24.3% of the population living below the poverty line, including 37.5% of under eighteens and 17.2% of those over 64.