Kensett, Iowa

From Wikipedia, the free encyclopedia

Kensett is a city in Worth County, Iowa, United States. The population was 280 at the 2000 census.

[edit] Geography

Kensett is located at 43°21′14″N, 93°12′31″W (43.353859, -93.208560)^GR1.

According to the United States Census Bureau, the city has a total area of 4.0 km² (1.5 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 280 people, 131 households, and 77 families residing in the city. The population density was 70.7/km² (183.5/mi²). There were 143 housing units at an average density of 36.1/km² (93.7/mi²). The racial makeup of the city was 100.00% White.

There were 131 households out of which 19.8% had children under the age of 18 living with them, 51.1% were married couples living together, 4.6% had a female householder with no husband present, and 40.5% were non-families. 35.1% of all households were made up of individuals and 18.3% had someone living alone who was 65 years of age or older. The average household size was 2.14 and the average family size was 2.67.

In the city the population was spread out with 20.0% under the age of 18, 7.5% from 18 to 24, 26.8% from 25 to 44, 26.8% from 45 to 64, and 18.9% who were 65 years of age or older. The median age was 44 years. For every 100 females there were 101.4 males. For every 100 females age 18 and over, there were 100.0 males.

The median income for a household in the city was $30,500, and the median income for a family was $40,000. Males had a median income of $29,000 versus $20,179 for females. The per capita income for the city was $15,601. About 14.3% of families and 17.2% of the population were below the poverty line, including 35.1% of those under the age of eighteen and 14.0% of those sixty five or over.