Jefferson, Maine
From Wikipedia, the free encyclopedia
Jefferson is a town in Lincoln County, Maine, United States. The population was 2,388 at the 2000 census.
[edit] Geography
According to the United States Census Bureau, the town has a total area of 151.9 km² (58.6 mi²). 136.5 km² (52.7 mi²) of it is land and 15.4 km² (6.0 mi²) of it (10.16%) is water.
[edit] Demographics
As of the census2 of 2000, there were 2,388 people, 945 households, and 687 families residing in the town. The population density was 17.5/km² (45.3/mi²). There were 1,427 housing units at an average density of 10.5/km² (27.1/mi²). The racial makeup of the town was 98.83% White, 0.08% African American, 0.04% Native American, 0.17% Asian, 0.13% from other races, and 0.75% from two or more races. Hispanic or Latino of any race were 0.34% of the population.
There were 945 households out of which 31.7% had children under the age of 18 living with them, 62.4% were married couples living together, 6.3% had a female householder with no husband present, and 27.2% were non-families. 21.2% of all households were made up of individuals and 9.1% had someone living alone who was 65 years of age or older. The average household size was 2.52 and the average family size was 2.91.
In the town the population was spread out with 24.6% under the age of 18, 5.5% from 18 to 24, 28.7% from 25 to 44, 26.3% from 45 to 64, and 14.9% who were 65 years of age or older. The median age was 40 years. For every 100 females there were 97.4 males. For every 100 females age 18 and over, there were 98.6 males.
The median income for a household in the town was $42,311, and the median income for a family was $45,694. Males had a median income of $30,865 versus $25,430 for females. The per capita income for the town was $20,298. About 7.3% of families and 12.3% of the population were below the poverty line, including 17.4% of those under age 18 and 11.4% of those age 65 or over.
