Jackson, Nebraska

From Wikipedia, the free encyclopedia

Jackson is a village in Dakota County, Nebraska, United States. It is part of the Sioux City/Iowa/Nebraska/South Dakota Metropolitan Statistical Area. The population was 205 at the 2000 census.

[edit] Geography

Jackson is located at 42°26′56″N, 96°33′58″W (42.448789, -96.566207)^GR1.

According to the United States Census Bureau, the village has a total area of 0.4 km² (0.2 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 205 people, 83 households, and 57 families residing in the village. The population density was 465.6/km² (1,175.0/mi²). There were 90 housing units at an average density of 204.4/km² (515.9/mi²). The racial makeup of the village was 99.02% White, 0.49% Native American and 0.49% Asian.

There were 83 households out of which 32.5% had children under the age of 18 living with them, 54.2% were married couples living together, 10.8% had a female householder with no husband present, and 31.3% were non-families. 30.1% of all households were made up of individuals and 15.7% had someone living alone who was 65 years of age or older. The average household size was 2.47 and the average family size was 3.09.

In the village the population was spread out with 26.8% under the age of 18, 7.3% from 18 to 24, 26.8% from 25 to 44, 24.4% from 45 to 64, and 14.6% who were 65 years of age or older. The median age was 38 years. For every 100 females there were 101.0 males. For every 100 females age 18 and over, there were 100.0 males.

The median income for a household in the village was $50,833, and the median income for a family was $59,063. Males had a median income of $31,500 versus $22,917 for females. The per capita income for the village was $20,771. About 3.2% of families and 1.9% of the population were below the poverty line, including none of those under the age of eighteen and 13.3% of those sixty five or over.