User talk:Itaj Sherman

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[edit] Portuguese in Hebrew Wikibooks

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BTW i write a pronunciation guide of brazilian portuguese in the hebrew wikibooks. it's not as thourough as the phonology article here, but it's more practical for people who have only the very basic linguistic knowledge (of junior high) and want to learn portuguese. i don't use there terms like "allophones" or "phonemes". --itaj 23:17, 22 June 2006 (UTC)

You are free to translate the English language article as you see fit, of course. ;-) You might also find the article on the Orthography of Portuguese useful. Regards. FilipeS 11:47, 23 June 2006 (UTC)

[edit] a question

let (Ω,Σ), be a measurable space. i'm talking here about real-value signed finite measures on this space. let M be a set of measures.

let N be the set of all measures absolutely continuous with respect to a measure in the linear span of measures in M. i.e. N := \{ \nu : \exists \mu\in span(M)\ (\nu<<\mu) \}

for a measure μ i'll denote {singl}(\mu) := \{ \nu : \nu\perp\mu \}. the set of measures mutually singular to μ.

and for a set of measures L. {Singl}(L) := \{ \nu : \forall \mu\in L\ (\mu\perp\nu) \}. the set of all measures mutually singular to all measures in L.

my question is if the above implies that N = Singl(Singl(N)) i know this is true if there's only one measure in M, but i need to know about infinite set M, countable and bigger. --itaj 04:05, 12 May 2006 (UTC)

If span is in the sense of vector spaces, then no. Consider M:=\{\delta_n:n\in N\}. Then \sum 2^{-n}\delta_n\not\in span(M) or N, but it is in singl(singl(N)). (Cj67 23:42, 25 June 2006 (UTC))
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