Indiantown, Florida

From Wikipedia, the free encyclopedia

Indiantown is a census-designated place (CDP) in Martin County, Florida, United States. The population was 5,588 at the 2000 census.

1 Geography
2 Demographics
3 Payson Park
4 External links

[edit] Geography

Indiantown is located at 27°1′35″N, 80°28′22″W (27.026343, -80.472758)^GR1.

According to the United States Census Bureau, the CDP has a total area of 15.5 km² (6.0 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 5,588 people, 1,648 households, and 1,264 families residing in the CDP. The population density was 361.4/km² (936.2/mi²). There were 1,807 housing units at an average density of 116.9/km² (302.7/mi²). The racial makeup of the CDP was 45.92% White, 20.99% African American, 2.29% Native American, 0.20% Asian, 0.97% Pacific Islander, 26.54% from other races, and 3.10% from two or more races. Hispanic or Latino of any race were 48.93% of the population.

There were 1,648 households out of which 33.7% had children under the age of 18 living with them, 54.9% were married couples living together, 13.7% had a female householder with no husband present, and 23.3% were non-families. 17.2% of all households were made up of individuals and 9.9% had someone living alone who was 65 years of age or older. The average household size was 3.39 and the average family size was 3.59.

In the CDP the population was spread out with 31.2% under the age of 18, 11.4% from 18 to 24, 25.6% from 25 to 44, 15.7% from 45 to 64, and 16.2% who were 65 years of age or older. The median age was 30 years. For every 100 females there were 123.0 males. For every 100 females age 18 and over, there were 123.2 males.

The median income for a household in the CDP was $28,977, and the median income for a family was $30,675. Males had a median income of $17,810 versus $19,063 for females. The per capita income for the CDP was $11,085. About 18.8% of families and 23.8% of the population were below the poverty line, including 31.3% of those under age 18 and 7.0% of those age 65 or over.