Hyattville, Wyoming

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Hyattville is a census-designated place (CDP) in Big Horn County, Wyoming, United States. The population was 73 at the 2000 census.

[edit] Geography

Hyattville is located at 44°14′56″N, 107°36′20″W (44.248802, -107.605677)^GR1.

According to the United States Census Bureau, the CDP has a total area of 10.5 km² (4.1 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 73 people, 32 households, and 20 families residing in the CDP. The population density was 6.9/km² (17.9/mi²). There were 62 housing units at an average density of 5.9/km² (15.2/mi²). The racial makeup of the CDP was 97.26% White, 1.37% Asian, and 1.37% from two or more races.

There were 32 households out of which 25.0% had children under the age of 18 living with them, 53.1% were married couples living together, 9.4% had a female householder with no husband present, and 34.4% were non-families. 31.3% of all households were made up of individuals and 15.6% had someone living alone who was 65 years of age or older. The average household size was 2.28 and the average family size was 2.81.

In the CDP the population was spread out with 26.0% under the age of 18, 5.5% from 18 to 24, 21.9% from 25 to 44, 27.4% from 45 to 64, and 19.2% who were 65 years of age or older. The median age was 42 years. For every 100 females there were 102.8 males. For every 100 females age 18 and over, there were 100.0 males.

The median income for a household in the CDP was $23,125, and the median income for a family was $45,625. Males had a median income of $29,375 versus $17,813 for females. The per capita income for the CDP was $20,324. There were 11.8% of families and 6.5% of the population living below the poverty line, including no under eighteens and none of those over 64.