Huntley, Nebraska

From Wikipedia, the free encyclopedia

Huntley is a village in Harlan County, Nebraska, United States. The population was 67 at the 2000 census.

[edit] Geography

Huntley is located at 40°12′35″N, 99°17′31″W (40.209586, -99.291873)^GR1.

According to the United States Census Bureau, the village has a total area of 0.9 km² (0.3 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 67 people, 25 households, and 18 families residing in the village. The population density was 73.9/km² (190.3/mi²). There were 28 housing units at an average density of 30.9/km² (79.5/mi²). The racial makeup of the village was 100.00% White. Hispanic or Latino of any race were 1.49% of the population.

There were 25 households out of which 36.0% had children under the age of 18 living with them, 68.0% were married couples living together, 4.0% had a female householder with no husband present, and 28.0% were non-families. 24.0% of all households were made up of individuals and 8.0% had someone living alone who was 65 years of age or older. The average household size was 2.68 and the average family size was 3.28.

In the village the population was spread out with 29.9% under the age of 18, 4.5% from 18 to 24, 38.8% from 25 to 44, 17.9% from 45 to 64, and 9.0% who were 65 years of age or older. The median age was 38 years. For every 100 females there were 139.3 males. For every 100 females age 18 and over, there were 123.8 males.

The median income for a household in the village was $41,250, and the median income for a family was $42,917. Males had a median income of $25,000 versus $18,750 for females. The per capita income for the village was $16,375. There were 4.3% of families and 5.3% of the population living below the poverty line, including no under eighteens and 20.0% of those over 64.