Hunlock Township, Pennsylvania

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Hunlock Township is a township in Luzerne County, Pennsylvania, United States. The population was 2,568 at the 2000 census.

[edit] Geography

According to the United States Census Bureau, the township has a total area of 55.9 km² (21.6 mi²). 55.1 km² (21.3 mi²) of it is land and 0.7 km² (0.3 mi²) of it (1.30%) is water.

[edit] Demographics

As of the census² of 2000, there were 2,568 people, 952 households, and 753 families residing in the township. The population density was 46.6/km² (120.6/mi²). There were 988 housing units at an average density of 17.9/km² (46.4/mi²). The racial makeup of the township was 98.83% White, 0.12% African American, 0.04% Native American, 0.43% Asian, and 0.58% from two or more races. Hispanic or Latino of any race were 0.04% of the population.

There were 952 households out of which 34.3% had children under the age of 18 living with them, 67.0% were married couples living together, 8.1% had a female householder with no husband present, and 20.9% were non-families. 17.9% of all households were made up of individuals and 8.6% had someone living alone who was 65 years of age or older. The average household size was 2.70 and the average family size was 3.05.

In the township the population was spread out with 23.8% under the age of 18, 7.6% from 18 to 24, 29.0% from 25 to 44, 26.7% from 45 to 64, and 12.9% who were 65 years of age or older. The median age was 39 years. For every 100 females there were 103.8 males. For every 100 females age 18 and over, there were 101.3 males.

The median income for a household in the township was $38,309, and the median income for a family was $41,071. Males had a median income of $28,641 versus $23,611 for females. The per capita income for the township was $15,541. About 6.7% of families and 8.2% of the population were below the poverty line, including 9.3% of those under age 18 and 8.7% of those age 65 or over.