Hubbell, Nebraska

From Wikipedia, the free encyclopedia

Hubbell is a village in Thayer County, Nebraska, United States. The population was 73 at the 2000 census.

[edit] Geography

Hubbell is located at 40°0′35″N, 97°29′49″W (40.009665, -97.496977)^GR1.

According to the United States Census Bureau, the village has a total area of 0.8 km² (0.3 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 73 people, 29 households, and 20 families residing in the village. The population density was 88.1/km² (230.0/mi²). There were 43 housing units at an average density of 51.9/km² (135.5/mi²). The racial makeup of the village was 98.63% White and 1.37% African American. Hispanic or Latino of any race were 2.74% of the population.

There were 29 households out of which 27.6% had children under the age of 18 living with them, 69.0% were married couples living together, 3.4% had a female householder with no husband present, and 27.6% were non-families. 20.7% of all households were made up of individuals and 10.3% had someone living alone who was 65 years of age or older. The average household size was 2.52 and the average family size was 2.90.

In the village the population was spread out with 27.4% under the age of 18, 2.7% from 18 to 24, 26.0% from 25 to 44, 28.8% from 45 to 64, and 15.1% who were 65 years of age or older. The median age was 42 years. For every 100 females there were 97.3 males. For every 100 females age 18 and over, there were 89.3 males.

The median income for a household in the village was $37,500, and the median income for a family was $38,125. Males had a median income of $24,375 versus $14,250 for females. The per capita income for the village was $14,630. There were 8.8% of families and 20.6% of the population living below the poverty line, including 45.2% of under eighteens and 14.3% of those over 64.