Highland, Wisconsin

From Wikipedia, the free encyclopedia

Highland is a village in Iowa County, Wisconsin, United States. The population was 855 at the 2000 census. The village is located within the Town of Highland. There is also another Town of Highland in Douglas County, Wisconsin.

[edit] Geography

Highland is located at 43°2′46″N, 90°22′44″W (43.046347, -90.379083)^GR1.

According to the United States Census Bureau, the village has a total area of 2.9 km² (1.1 mi²). None of the area is covered with water.

[edit] Demographics

As of the census^GR2 of 2000, there were 855 people, 348 households, and 228 families residing in the village. The population density was 292.1/km² (756.0/mi²). There were 369 housing units at an average density of 126.1/km² (326.3/mi²). The racial makeup of the village was 100.00% White. 0.35% of the population were Hispanic or Latino of any race.

There were 348 households out of which 29.6% had children under the age of 18 living with them, 54.6% were married couples living together, 8.9% had a female householder with no husband present, and 34.2% were non-families. 29.3% of all households were made up of individuals and 18.1% had someone living alone who was 65 years of age or older. The average household size was 2.44 and the average family size was 3.03.

In the village the population was spread out with 23.9% under the age of 18, 11.1% from 18 to 24, 27.4% from 25 to 44, 19.2% from 45 to 64, and 18.5% who were 65 years of age or older. The median age was 36 years. For every 100 females there were 96.1 males. For every 100 females age 18 and over, there were 90.4 males.

The median income for a household in the village was $37,228, and the median income for a family was $44,875. Males had a median income of $30,250 versus $22,000 for females. The per capita income for the village was $16,176. About 4.8% of families and 7.2% of the population were below the poverty line, including 2.4% of those under age 18 and 13.2% of those age 65 or over.