Henry, Tennessee

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Henry is a town in Henry County, Tennessee, United States. The population was 520 at the 2000 census.

1 Geography
2 Demographics
3 Media
4 External links

[edit] Geography

Henry is located at 36°12′8″N, 88°25′6″W (36.202197, -88.418208)^GR1.

According to the United States Census Bureau, the town has a total area of 3.1 km² (1.2 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 520 people, 191 households, and 141 families residing in the town. The population density was 167.3/km² (434.2/mi²). There were 207 housing units at an average density of 66.6/km² (172.9/mi²). The racial makeup of the town was 82.88% White, 14.42% African American, 0.38% Native American, 2.31% from other races. Hispanic or Latino of any race were 6.73% of the population.

There were 191 households out of which 40.3% had children under the age of 18 living with them, 52.4% were married couples living together, 19.4% had a female householder with no husband present, and 25.7% were non-families. 20.9% of all households were made up of individuals and 7.9% had someone living alone who was 65 years of age or older. The average household size was 2.72 and the average family size was 3.16.

In the town the population was spread out with 30.2% under the age of 18, 8.7% from 18 to 24, 31.5% from 25 to 44, 19.0% from 45 to 64, and 10.6% who were 65 years of age or older. The median age was 33 years. For every 100 females there were 89.8 males. For every 100 females age 18 and over, there were 88.1 males.

The median income for a household in the town was $26,333, and the median income for a family was $30,714. Males had a median income of $21,250 versus $21,667 for females. The per capita income for the town was $12,663. About 15.0% of families and 18.7% of the population were below the poverty line, including 22.4% of those under age 18 and 12.5% of those age 65 or over.