Hawley, Texas

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Hawley is a city in Jones County, Texas, United States. The population was 646 at the 2000 census.

1 Geography
2 Demographics
3 Education
4 External links

[edit] Geography

Hawley is located at 32°36′43″N, 99°48′48″W (32.612023, -99.813315)^GR1.

According to the United States Census Bureau, the city has a total area of 7.6 km² (2.9 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 646 people, 239 households, and 184 families residing in the city. The population density was 84.8/km² (219.7/mi²). There were 264 housing units at an average density of 34.7/km² (89.8/mi²). The racial makeup of the city was 96.44% White, 0.15% African American, 0.93% Asian, 1.70% from other races, and 0.77% from two or more races. Hispanic or Latino of any race were 4.18% of the population.

There were 239 households out of which 39.3% had children under the age of 18 living with them, 63.6% were married couples living together, 9.2% had a female householder with no husband present, and 22.6% were non-families. 20.1% of all households were made up of individuals and 10.9% had someone living alone who was 65 years of age or older. The average household size was 2.70 and the average family size was 3.11.

In the city the population was spread out with 30.7% under the age of 18, 7.3% from 18 to 24, 28.5% from 25 to 44, 22.3% from 45 to 64, and 11.3% who were 65 years of age or older. The median age was 34 years. For every 100 females there were 96.4 males. For every 100 females age 18 and over, there were 94.8 males.

The median income for a household in the city was $31,771, and the median income for a family was $36,625. Males had a median income of $25,893 versus $21,071 for females. The per capita income for the city was $14,879. About 9.3% of families and 13.0% of the population were below the poverty line, including 18.8% of those under age 18 and 15.9% of those age 65 or over.