Hölder's inequality

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In mathematical analysis, Hölder's inequality, named after Otto Hölder, is a fundamental inequality relating Lp spaces: let S be a measure space, let 1 ≤ p, q ≤ ∞ with 1/p + 1/q = 1, let f be in Lp(S) and g be in Lq(S). Then fg is in L1(S) and

\|fg\|_1 \le \|f\|_p \|g\|_q.

The numbers p and q above are said to be Hölder conjugates of each other.

Hölder's inequality is used to prove the generalization of the triangle inequality in the space Lp, the Minkowski inequality, and also to establish that Lp is dual to Lq.

Hölder's inequality was first found by L. J. Rogers (1888), and rediscovered by Hölder (1889).

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[edit] Notable special cases

\sum_{k=1}^n |x_k y_k| \leq \left( \sum_{k=1}^n |x_k|^p \right)^{1/p} \left( \sum_{k=1}^n |y_k|^q \right)^{1/q}.
  • If S = N with the counting measure, then we get Holder's inequality for sequences from lp spaces
\sum\limits_{n=1}^{\infty} |x_n \cdot y_n| \le \left( \sum\limits_{n=1}^{\infty} |x_n|^p \right)^{1/p} \cdot \left( \sum\limits_{n=1}^{\infty} |y_n|^q \right)^{1/q},\; \forall x \in \ell^p, y\in \ell^q.
\left|\int f(x)g(x)\,dx\right|\leq \int \bigg| f(x)g(x)\bigg| \, dx \leq\left(\int \left|f(x)\right|^p\,dx \right)^{1/p}\cdot \left(\int\left|g(x)\right|^q\,dx\right)^{1/q}.
\mathbb{E}|XY| \le \left(\mathbb{E}|X|^p\right)^{1/p} \cdot \left( \mathbb{E}|Y|^q \right)^{1/q},\; \forall X \in L^p, Y \in L^q.

The inequality becomes equality when

| Y | = k | X | p − 1

for some constant k.

[edit] Generalization

The following generalization can be proven by induction.

Assume p_k\geq 1, k=1,\ldots, n are such that

\sum_{k=1}^n \frac{1}{p_k}=1.

Assume that u_k\in L^{p_k}(S). Then \prod_{k=1}^n u_k \in L^1(S) and

\left\|\prod_{k=1}^n u_k\right\|_{\displaystyle L^1(S)}\leq \prod_{k=1}^n \|u_k\|_{\displaystyle L^{p_k}(S)}.

[edit] Proof

We want to prove that

\sum a_i b_i \le (\sum a_i^p)^{\frac {1}{p}} \cdot (\sum b_i^q)^{\frac {1}{q}}.

We observe that both sides are homogeneous of degree 1 in a and b, so by multiplying the sequences a and b by constants we can assume that Σap = Σbq = 1 (in which case the right hand side of the inequality is 1).

But this special case follows from Young's inequality abap/p + bq/q as follows:

\sum a_ib_i \le \frac {1}{p} \sum a_i^p +   \frac {1}{q} \sum b_i^q = \frac {1}{p} + \frac {1}{q} = 1.

[edit] References

  • L.P. Kuptsov, "Hölder inequality" SpringerLink Encyclopaedia of Mathematics (2001)
  • O. Hölder, Ueber einen Mittelwerthsatz Nachr. Ges. Wiss. Göttingen (1889) pp. 38–47
  • G.H. Hardy, J.E. Littlewood, G. Pólya, Inequalities , Cambridge Univ. Press (1934)
  • L J. Rogers, An extension of a certain theorem in inequalities Messenger of math 17, 145-150.