Guernsey, Wyoming

From Wikipedia, the free encyclopedia

Guernsey is a town in Platte County, Wyoming, United States. The population was 1,147 at the 2000 census.

[edit] Geography

Guernsey is located at 42°16′2″N, 104°44′35″W (42.267251, -104.743187)^GR1.

According to the United States Census Bureau, the town has a total area of 2.8 km² (1.1 mi²). 2.8 km² (1.1 mi²) of it is land and 0.92% is water.

[edit] Demographics

As of the census^GR2 of 2000, there were 1,147 people, 504 households, and 312 families residing in the town. The population density was 413.9/km² (1,067.3/mi²). There were 612 housing units at an average density of 220.8/km² (569.5/mi²). The racial makeup of the town was 91.54% White, 0.17% African American, 1.05% Native American, 0.17% Asian, 3.75% from other races, and 3.31% from two or more races. Hispanic or Latino of any race were 8.11% of the population.

There were 504 households out of which 30.4% had children under the age of 18 living with them, 49.0% were married couples living together, 9.9% had a female householder with no husband present, and 37.9% were non-families. 33.3% of all households were made up of individuals and 15.7% had someone living alone who was 65 years of age or older. The average household size was 2.28 and the average family size was 2.89.

In the town the population was spread out with 26.8% under the age of 18, 7.1% from 18 to 24, 23.8% from 25 to 44, 26.9% from 45 to 64, and 15.3% who were 65 years of age or older. The median age was 40 years. For every 100 females there were 96.4 males. For every 100 females age 18 and over, there were 89.6 males.

The median income for a household in the town was $30,758, and the median income for a family was $38,958. Males had a median income of $37,778 versus $17,656 for females. The per capita income for the town was $14,897. About 7.6% of families and 10.9% of the population were below the poverty line, including 11.7% of those under age 18 and 19.6% of those age 65 or over.