Greenville, Iowa

From Wikipedia, the free encyclopedia

Greenville is a city in Clay County, Iowa, United States. The population was 93 at the 2000 census.

[edit] Geography

Greenville is located at 43°0′58″N, 95°8′44″W (43.016091, -95.145464)^GR1.

According to the United States Census Bureau, the city has a total area of 0.5 km² (0.2 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 93 people, 34 households, and 24 families residing in the city. The population density was 199.5/km² (507.9/mi²). There were 37 housing units at an average density of 79.4/km² (202.1/mi²). The racial makeup of the city was 100.00% White.

There were 34 households out of which 38.2% had children under the age of 18 living with them, 70.6% were married couples living together, 2.9% had a female householder with no husband present, and 26.5% were non-families. 23.5% of all households were made up of individuals and 11.8% had someone living alone who was 65 years of age or older. The average household size was 2.74 and the average family size was 3.20.

In the city the population was spread out with 31.2% under the age of 18, 5.4% from 18 to 24, 26.9% from 25 to 44, 26.9% from 45 to 64, and 9.7% who were 65 years of age or older. The median age was 38 years. For every 100 females there were 102.2 males. For every 100 females age 18 and over, there were 93.9 males.

The median income for a household in the city was $29,531, and the median income for a family was $37,500. Males had a median income of $34,063 versus $21,250 for females. The per capita income for the city was $22,217. There were 18.8% of families and 19.2% of the population living below the poverty line, including 23.8% of under eighteens and none of those over 64.