Gillett Grove, Iowa

From Wikipedia, the free encyclopedia

Gillett Grove is a city in Clay County, Iowa, United States. The population was 55 at the 2000 census.

[edit] Geography

Gillett Grove is located at 43°0′52″N, 95°2′12″W (43.014514, -95.036576)^GR1.

According to the United States Census Bureau, the city has a total area of 0.5 km² (0.2 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 55 people, 28 households, and 19 families residing in the city. The population density was 111.8/km² (291.6/mi²). There were 30 housing units at an average density of 61.0/km² (159.1/mi²). The racial makeup of the city was 98.18% White, and 1.82% from two or more races.

There were 28 households out of which 32.1% had children under the age of 18 living with them, 46.4% were married couples living together, 10.7% had a female householder with no husband present, and 32.1% were non-families. 32.1% of all households were made up of individuals and 10.7% had someone living alone who was 65 years of age or older. The average household size was 1.96 and the average family size was 2.21.

In the city the population was spread out with 18.2% under the age of 18, 10.9% from 18 to 24, 21.8% from 25 to 44, 25.5% from 45 to 64, and 23.6% who were 65 years of age or older. The median age was 44 years. For every 100 females there were 89.7 males. For every 100 females age 18 and over, there were 87.5 males.

The median income for a household in the city was $21,429, and the median income for a family was $17,292. Males had a median income of $18,750 versus $21,250 for females. The per capita income for the city was $12,337. There were 13.3% of families and 28.3% of the population living below the poverty line, including 18.2% of under eighteens and none of those over 64.