Gilbertville, Iowa

From Wikipedia, the free encyclopedia

Gilbertville is a city in Black Hawk County, Iowa, United States. The population was 767 at the 2000 census.

[edit] Geography

Gilbertville is located at 42°25′2″N, 92°12′50″W (42.417252, -92.213964)^GR1.

According to the United States Census Bureau, the city has a total area of 1.0 km² (0.4 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 767 people, 297 households, and 212 families residing in the city. The population density was 759.3/km² (1,957.8/mi²). There were 305 housing units at an average density of 302.0/km² (778.5/mi²). The racial makeup of the city was 99.48% White, 0.13% African American, and 0.39% from two or more races. Hispanic or Latino of any race were 0.78% of the population.

There were 297 households out of which 35.0% had children under the age of 18 living with them, 61.3% were married couples living together, 7.7% had a female householder with no husband present, and 28.6% were non-families. 25.9% of all households were made up of individuals and 16.2% had someone living alone who was 65 years of age or older. The average household size was 2.58 and the average family size was 3.14.

In the city the population was spread out with 27.1% under the age of 18, 8.3% from 18 to 24, 28.4% from 25 to 44, 19.6% from 45 to 64, and 16.6% who were 65 years of age or older. The median age was 38 years. For every 100 females there were 97.2 males. For every 100 females age 18 and over, there were 98.2 males.

The median income for a household in the city was $41,490, and the median income for a family was $47,917. Males had a median income of $31,458 versus $24,286 for females. The per capita income for the city was $18,367. About 4.0% of families and 4.0% of the population were below the poverty line, including 5.9% of those under age 18 and 7.6% of those age 65 or over.