Garwin, Iowa

From Wikipedia, the free encyclopedia

Garwin is a city in Tama County, Iowa, United States. As of the 2000 census, the city had a total population of 565.

[edit] Geography

Garwin is located at 42°5′41″N, 92°40′36″W (42.094635, -92.676653)^GR1.

According to the United States Census Bureau, the city has a total area of 2.6 km² (1.0 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 565 people, 230 households, and 158 families residing in the city. The population density was 218.1/km² (564.0/mi²). There were 248 housing units at an average density of 95.8/km² (247.6/mi²). The racial makeup of the city was 98.58% White, 0.88% from other races, and 0.53% from two or more races. Hispanic or Latino of any race were 1.77% of the population.

There were 230 households out of which 33.9% had children under the age of 18 living with them, 57.0% were married couples living together, 8.7% had a female householder with no husband present, and 30.9% were non-families. 26.1% of all households were made up of individuals and 13.0% had someone living alone who was 65 years of age or older. The average household size was 2.46 and the average family size was 2.92.

In the city the population was spread out with 27.8% under the age of 18, 6.7% from 18 to 24, 27.3% from 25 to 44, 24.6% from 45 to 64, and 13.6% who were 65 years of age or older. The median age was 36 years. For every 100 females there were 92.8 males. For every 100 females age 18 and over, there were 88.0 males.

The median income for a household in the city was $38,269, and the median income for a family was $45,938. Males had a median income of $31,528 versus $24,250 for females. The per capita income for the city was $16,660. About 2.4% of families and 5.2% of the population were below the poverty line, including 4.4% of those under age 18 and 11.8% of those age 65 or over.