Frederic, Wisconsin

From Wikipedia, the free encyclopedia

Frederic is a village in Polk County, Wisconsin, United States. The population was 1,262 at the 2000 census.

[edit] Geography

Frederic is located at 45°39′32″N, 92°28′1″W (45.658797, -92.466921)^GR1.

According to the United States Census Bureau, the village has a total area of 4.1 km² (1.6 mi²). 4.0 km² (1.5 mi²) of it is land and 0.2 km² (0.1 mi²) of it (4.38%) is water.

[edit] Demographics

As of the census^GR2 of 2000, there were 1,262 people, 536 households, and 286 families residing in the village. The population density was 316.4/km² (820.6/mi²). There were 586 housing units at an average density of 146.9/km² (381.1/mi²). The racial makeup of the village was 97.78% White, 0.08% African American, 1.19% Native American, 0.16% Asian, and 0.79% from two or more races. Hispanic or Latino of any race were 0.40% of the population.

There were 536 households out of which 23.1% had children under the age of 18 living with them, 41.0% were married couples living together, 9.1% had a female householder with no husband present, and 46.5% were non-families. 42.2% of all households were made up of individuals and 25.2% had someone living alone who was 65 years of age or older. The average household size was 2.15 and the average family size was 2.99.

In the village the population was spread out with 23.0% under the age of 18, 6.3% from 18 to 24, 22.3% from 25 to 44, 16.9% from 45 to 64, and 31.5% who were 65 years of age or older. The median age was 44 years. For every 100 females there were 79.0 males. For every 100 females age 18 and over, there were 70.2 males.

The median income for a household in the village was $25,380, and the median income for a family was $40,000. Males had a median income of $30,987 versus $19,813 for females. The per capita income for the village was $15,685. About 5.6% of families and 10.9% of the population were below the poverty line, including 8.5% of those under age 18 and 21.1% of those age 65 or over.