Franklin, Arkansas

From Wikipedia, the free encyclopedia

Franklin is a town in Izard County, Arkansas, United States. The population was 184 at the 2000 census.

[edit] Geography

Franklin is located at 36°10′31″N, 91°45′59″W (36.175324, -91.766494)^GR1.

According to the United States Census Bureau, the town has a total area of 5.3 km² (2.0 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 184 people, 80 households, and 52 families residing in the town. The population density was 35.0/km² (90.7/mi²). There were 89 housing units at an average density of 16.9/km² (43.9/mi²). The racial makeup of the town was 97.83% White, 1.09% Native American, 1.09% from other races. 2.72% of the population were Hispanic or Latino of any race.

There were 80 households out of which 23.8% had children under the age of 18 living with them, 50.0% were married couples living together, 7.5% had a female householder with no husband present, and 35.0% were non-families. 31.3% of all households were made up of individuals and 25.0% had someone living alone who was 65 years of age or older. The average household size was 2.30 and the average family size was 2.81.

In the town the population was spread out with 21.7% under the age of 18, 11.4% from 18 to 24, 27.2% from 25 to 44, 21.7% from 45 to 64, and 17.9% who were 65 years of age or older. The median age was 38 years. For every 100 females there were 85.9 males. For every 100 females age 18 and over, there were 94.6 males.

The median income for a household in the town was $19,750, and the median income for a family was $26,250. Males had a median income of $20,341 versus $19,167 for females. The per capita income for the town was $13,434. About 13.5% of families and 19.6% of the population were below the poverty line, including 17.6% of those under the age of eighteen and 34.1% of those sixty five or over.