Edwardsville, Alabama

From Wikipedia, the free encyclopedia

Edwardsville is a town in Cleburne County, Alabama, United States. At the 2000 census the population was 186.

[edit] Geography

Edwardsville is located at 33°42'25.855" North, 85°30'38.016" West (33.707182, -85.510560)^GR1.

According to the U.S. Census Bureau, the town has a total area of 2.5 km² (1.0 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 186 people, 80 households, and 55 families residing in the town. The population density was 74.8/km² (194.0/mi²). There were 89 housing units at an average density of 35.8/km² (92.8/mi²). The racial makeup of the town was 98.39% White, 0.54% Black or African American, and 1.08% from two or more races. 0.54% of the population were Hispanic or Latino of any race.

There were 80 households out of which 25.0% had children under the age of 18 living with them, 58.8% were married couples living together, 7.5% had a female householder with no husband present, and 31.3% were non-families. 26.3% of all households were made up of individuals and 11.3% had someone living alone who was 65 years of age or older. The average household size was 2.33 and the average family size was 2.84.

In the town the population was spread out with 22.6% under the age of 18, 7.0% from 18 to 24, 27.4% from 25 to 44, 25.3% from 45 to 64, and 17.7% who were 65 years of age or older. The median age was 40 years. For every 100 females there were 111.4 males. For every 100 females age 18 and over, there were 100.0 males.

The median income for a household in the town was $19,808, and the median income for a family was $29,792. Males had a median income of $30,500 versus $21,250 for females. The per capita income for the town was $12,835. About 16.4% of families and 28.7% of the population were below the poverty line, including 26.4% of those under the age of eighteen and 20.0% of those sixty five or over.