Darboux derivative

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The Darboux derivative of a map between a manifold and a Lie group is a variant of the standard derivative. In a certain sense, it is arguably a more natural generalization of the single-variable derivative. It allows a generalization of the single-variable Fundamental Theorem of Calculus to higher dimensions, in a different vein than the generalization that is Stokes' Theorem.

1 Formal Definition
2 References

[edit] Formal Definition

Let $G$ be a Lie group, and let $\mathfrak{g}$ be its Lie algebra. Recall the Maurer-Cartan form, $ω G$ , the smooth $\mathfrak{g}$ -valued $1$ -form on $G$ defined by

ω G (X g) = (T g L g) - 1 X g

for all $g \in G$ and $X_g \in T_g G$ . Here $L g$ denotes left multiplication by the element $g \in G$ and $T g L g$ is its derivative at $g$ .

Now let $f:M \to G$ be a smooth function between a manifold $M$ and a Lie group $G$ . Let $\mathfrak{g}$ be the Lie algebra of $G$ . Then the Darboux derivative of $f$ is the smooth $\mathfrak{g}$ -valued $1$ -form

ω f : = f * ω G,

the pullback of $ω G$ by $f$ .

The map $f$ is called an integral or primitive of $ω f$ .

[edit] More Natural?

The reason that one might call the Darboux derivative a more natural generalization of the derivative of single-variable calculus is this. In single-variable calculus, the derivative $f'$ of a function $f: \mathbb{R} \to \mathbb{R}$ assigns to each point in the domain a single number. According to the more general manifold ideas of derivatives, the derivative assigns to each point in the domain a linear map from the tangent space at the domain point to the tangent space at the image point. This derivative encapsulates two pieces of data: the image of the domain point and the linear map. In single-variable calculus, we drop some information. We retain only the linear map, in the form of a scalar multiplying agent (i.e. a number).

One way to justify this convention of retaining only the linear map aspect of the derivative is to appeal to the (very simple) Lie group structure of $\mathbb{R}$ under addition. The tangent bundle of any Lie group can be trivialized via left (or right) multiplication. This means that every tangent space in $\mathbb{R}$ may be identified with the tangent space at the identity, $0$ , which is the Lie algebra of $\mathbb{R}$ . In this case, left and right multiplication are simply translation. By post-composing the manifold-type derivative with the tangent space trivialization, for each point in the domain we obtain a linear map from the tangent space at the domain point to the Lie algebra of $\mathbb{R}$ . In symbols, for each $x \in \mathbb{R}$ we look at the map

$v \in T_x \mathbb{R} \mapsto (T_{f(x)} L_{f(x)})^{-1} \circ (T_x f) v \in T_0 \mathbb{R}.$

Since the tangent spaces involved are one-dimensional, this linear map is just multiplication by some scalar. (This scalar can change depending on what basis we use for the vector spaces, but the canonical unit vector field $\frac{\partial}{\partial t}$ on $\mathbb{R}$ gives a canonical choice of basis, and hence a canonical choice of scalar.) This scalar is what we usually denote by $f'(x)$ .

[edit] Uniqueness of Primitives

If the manifold $M$ is connected, and $f,g: M \to G$ are both primitives of $ω f$ , i.e. $ω f = ω g$ , then there exists some constant $C \in G$ such that

$f(x) = C \cdot g(x)$ for all $x \in M$ .

This constant $C$ is of course the analogue of the constant that appears when taking an indefinite integral.

[edit] The Fundamental Theorem of Calculus

Recall the structural equation for the Maurer-Cartan form: $d \omega + \frac{1}{2} [\omega, \omega] = 0$ . This means that for all vector fields $X$ and $Y$ on $G$ and all $x \in G$ , we have

$(d \omega)_x (X_x, Y_x) + \frac{1}{2} [\omega_x(X_x), \omega_x(Y_x)] = 0.$

For any Lie algebra-valued $1$ -form on any smooth manifold, all the terms in this equation make sense, so for any such form we can ask whether or not it satisfies this structural equation.

The usual fundamental theorem of calculus for single-variable calculus has the following local generalization.

If a $\mathfrak{g}$ -valued $1$ -form $ω$ on $M$ satisfies the structural equation, then every point $p \in M$ has an open neighborhood $U$ and a smooth map $f: U \to G$ such that