Crete, Nebraska

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Crete is a city in Saline County, Nebraska, United States. The population was 6,028 at the 2000 census.

1 Geography
2 Demographics
3 Points of interest
4 External links

[edit] Geography

Crete is located at 40°37′29″N, 96°57′33″W (40.624790, -96.959178)^GR1.

According to the United States Census Bureau, the city has a total area of 6.1 km² (2.4 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 6,028 people, 2,078 households, and 1,317 families residing in the city. The population density was 982.0/km² (2,541.9/mi²). There were 2,188 housing units at an average density of 356.5/km² (922.7/mi²). The racial makeup of the city was 86.48% White, 0.76% African American, 0.73% Native American, 3.27% Asian, 0.03% Pacific Islander, 6.90% from other races, and 1.82% from two or more races. Hispanic or Latino of any race were 13.50% of the population.

There were 2,078 households out of which 34.2% had children under the age of 18 living with them, 49.4% were married couples living together, 8.9% had a female householder with no husband present, and 36.6% were non-families. 29.2% of all households were made up of individuals and 15.4% had someone living alone who was 65 years of age or older. The average household size was 2.54 and the average family size was 3.13.

In the city the population was spread out with 23.9% under the age of 18, 20.1% from 18 to 24, 24.3% from 25 to 44, 17.2% from 45 to 64, and 14.6% who were 65 years of age or older. The median age was 30 years. For every 100 females there were 96.7 males. For every 100 females age 18 and over, there were 93.8 males.

The median income for a household in the city was $34,098, and the median income for a family was $43,295. Males had a median income of $30,778 versus $25,459 for females. The per capita income for the city was $14,936. About 7.8% of families and 12.7% of the population were below the poverty line, including 11.3% of those under age 18 and 11.0% of those age 65 or over.