Colesburg, Iowa

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Colesburg is a city in Delaware County, Iowa, United States. The population was 412 at the 2000 census.

[edit] Geography

Colesburg is located at 42°38′24″N, 91°12′4″W (42.639999, -91.201246)^GR1.

According to the United States Census Bureau, the city has a total area of 0.8 km² (0.3 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 412 people, 185 households, and 123 families residing in the city. The population density was 548.5/km² (1,399.9/mi²). There were 198 housing units at an average density of 263.6/km² (672.8/mi²). The racial makeup of the city was 100.00% White.

There were 185 households out of which 24.3% had children under the age of 18 living with them, 60.0% were married couples living together, 4.9% had a female householder with no husband present, and 33.5% were non-families. 33.5% of all households were made up of individuals and 21.6% had someone living alone who was 65 years of age or older. The average household size was 2.23 and the average family size was 2.81.

In the city the population was spread out with 20.1% under the age of 18, 5.3% from 18 to 24, 23.1% from 25 to 44, 26.2% from 45 to 64, and 25.2% who were 65 years of age or older. The median age was 46 years. For every 100 females there were 88.1 males. For every 100 females age 18 and over, there were 84.8 males.

The median income for a household in the city was $33,068, and the median income for a family was $41,750. Males had a median income of $31,667 versus $17,396 for females. The per capita income for the city was $16,638. About 4.6% of families and 5.2% of the population were below the poverty line, including 1.1% of those under age 18 and 11.1% of those age 65 or over.