Campbell, Nebraska

From Wikipedia, the free encyclopedia

Campbell is a village in Franklin County, Nebraska, United States. The population was 387 at the 2000 census.

[edit] Geography

Campbell is located at 40°17′52″N, 98°43′52″W (40.297786, -98.731212)^GR1.

According to the United States Census Bureau, the village has a total area of 0.9 km² (0.4 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 387 people, 151 households, and 101 families residing in the village. The population density was 415.1/km² (1,068.9/mi²). There were 182 housing units at an average density of 195.2/km² (502.7/mi²). The racial makeup of the village was 98.19% White, 0.26% Native American, and 1.55% from two or more races. Hispanic or Latino of any race were 0.52% of the population.

There were 151 households out of which 27.8% had children under the age of 18 living with them, 51.0% were married couples living together, 9.9% had a female householder with no husband present, and 32.5% were non-families. 29.8% of all households were made up of individuals and 21.2% had someone living alone who was 65 years of age or older. The average household size was 2.32 and the average family size was 2.83.

In the village the population was spread out with 21.4% under the age of 18, 7.5% from 18 to 24, 20.7% from 25 to 44, 15.8% from 45 to 64, and 34.6% who were 65 years of age or older. The median age was 45 years. For every 100 females there were 86.1 males. For every 100 females age 18 and over, there were 88.8 males.

The median income for a household in the village was $26,000, and the median income for a family was $33,438. Males had a median income of $27,917 versus $16,750 for females. The per capita income for the village was $13,594. About 7.4% of families and 13.3% of the population were below the poverty line, including 14.3% of those under age 18 and 13.0% of those age 65 or over.