Bryant, South Dakota

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Bryant is a city in Hamlin County, South Dakota, United States. The population was 396 at the 2000 census.

[edit] Geography

Bryant is located at 44°35′24″N, 97°27′59″W (44.589916, -97.466401)^GR1.

According to the United States Census Bureau, the city has a total area of 1.4 km² (0.5 mi²), all land.

Bryant has been assigned the ZIP code 57221 and the FIPS place code 08060.

The city of Bryant was founded in 1886.

[edit] Demographics

As of the census^GR2 of 2000, there were 396 people, 172 households, and 94 families residing in the city. The population density was 288.5/km² (749.7/mi²). There were 204 housing units at an average density of 148.6/km² (386.2/mi²). The racial makeup of the city was 99.75% White, and 0.25% African American.

There were 172 households out of which 26.7% had children under the age of 18 living with them, 47.1% were married couples living together, 6.4% had a female householder with no husband present, and 44.8% were non-families. 41.3% of all households were made up of individuals and 27.3% had someone living alone who was 65 years of age or older. The average household size was 2.30 and the average family size was 3.24.

In the city the population was spread out with 27.5% under the age of 18, 9.1% from 18 to 24, 21.7% from 25 to 44, 15.4% from 45 to 64, and 26.3% who were 65 years of age or older. The median age was 40 years. For every 100 females there were 91.3 males. For every 100 females age 18 and over, there were 88.8 males.

The median income for a household in the city was $21,719, and the median income for a family was $33,393. Males had a median income of $25,208 versus $21,250 for females. The per capita income for the city was $13,989. About 5.7% of families and 9.4% of the population were below the poverty line, including 8.8% of those under age 18 and 8.7% of those age 65 or over.