Brokenstraw Township, Pennsylvania

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Brokenstraw Township is a township in Warren County, Pennsylvania, USA. The population was 2,068 at the 2000 census.

[edit] Geography

According to the United States Census Bureau, the township has a total area of 100.4 km² (38.8 mi²). 100.0 km² (38.6 mi²) of it is land and 0.4 km² (0.2 mi²) of it (0.41%) is water.

[edit] Demographics

As of the census² of 2000, there were 2,068 people, 765 households, and 520 families residing in the township. The population density was 20.7/km² (53.5/mi²). There were 953 housing units at an average density of 9.5/km² (24.7/mi²). The racial makeup of the township was 99.08% White, 0.39% Native American, 0.19% Asian, 0.05% from other races, and 0.29% from two or more races. Hispanic or Latino of any race were 0.10% of the population.

There were 765 households out of which 28.2% had children under the age of 18 living with them, 55.7% were married couples living together, 9.0% had a female householder with no husband present, and 32.0% were non-families. 26.5% of all households were made up of individuals and 13.6% had someone living alone who was 65 years of age or older. The average household size was 2.37 and the average family size was 2.88.

In the township the population was spread out with 20.5% under the age of 18, 5.5% from 18 to 24, 23.5% from 25 to 44, 23.3% from 45 to 64, and 27.2% who were 65 years of age or older. The median age was 45 years. For every 100 females there were 87.0 males. For every 100 females age 18 and over, there were 78.9 males.

The median income for a household in the township was $34,130, and the median income for a family was $41,574. Males had a median income of $34,327 versus $20,776 for females. The per capita income for the township was $16,924. About 7.6% of families and 10.8% of the population were below the poverty line, including 15.9% of those under age 18 and 12.3% of those age 65 or over.