Bradshaw, Nebraska

From Wikipedia, the free encyclopedia

Bradshaw is a village in York County, Nebraska, United States. The population was 336 at the 2000 census.

[edit] Geography

Bradshaw is located at 40°53′1″N, 97°44′51″W (40.883704, -97.747556)^GR1.

According to the United States Census Bureau, the village has a total area of 0.9 km² (0.3 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 336 people, 138 households, and 101 families residing in the village. The population density was 393.1/km² (1,009.4/mi²). There were 150 housing units at an average density of 175.5/km² (450.6/mi²). The racial makeup of the village was 97.02% White, 1.19% Native American, 0.89% from other races, and 0.89% from two or more races. Hispanic or Latino of any race were 0.89% of the population.

There were 138 households out of which 30.4% had children under the age of 18 living with them, 60.1% were married couples living together, 5.8% had a female householder with no husband present, and 26.8% were non-families. 23.9% of all households were made up of individuals and 11.6% had someone living alone who was 65 years of age or older. The average household size was 2.43 and the average family size was 2.85.

In the village the population was spread out with 25.9% under the age of 18, 9.5% from 18 to 24, 26.2% from 25 to 44, 25.0% from 45 to 64, and 13.4% who were 65 years of age or older. The median age was 38 years. For every 100 females there were 96.5 males. For every 100 females age 18 and over, there were 99.2 males.

The median income for a household in the village was $37,969, and the median income for a family was $40,000. Males had a median income of $28,611 versus $16,125 for females. The per capita income for the village was $15,660. About 7.0% of families and 9.0% of the population were below the poverty line, including 11.8% of those under age 18 and 4.8% of those age 65 or over.