Talk:Borel–Carathéodory theorem

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[edit] Question about the proof

Why is |f(z)-2A| \ge |f(z)| for | z | = R? Note that A is defined as the supremum over the disc with radius r < R. -- Jitse Niesen (talk) 13:20, 6 September 2005 (UTC)

That's really the triangle inequality, in the form under Consequences on that page, isn't it? Charles Matthews 16:08, 6 September 2005 (UTC)

I can see that |f(z)-2A| \ge |f(z)| if |z| = r, but not if |z| = R. -- Jitse Niesen (talk) 16:40, 6 September 2005 (UTC)

Now fixed. It turns out the statement of the theorem was wrong. -- Jitse Niesen (talk) 18:23, 15 September 2005 (UTC)

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