Bode, Iowa

From Wikipedia, the free encyclopedia

Bode is a city in Humboldt County, Iowa, United States. The population was 327 at the 2000 census.

[edit] Geography

Bode is located at 42°52′2″N, 94°17′16″W (42.867146, -94.287910)^GR1.

According to the United States Census Bureau, the city has a total area of 1.1 km² (0.4 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 327 people, 148 households, and 95 families residing in the city. The population density was 307.9/km² (797.6/mi²). There were 168 housing units at an average density of 158.2/km² (409.8/mi²). The racial makeup of the city was 95.11% White, 1.53% Asian, 2.75% Pacific Islander, and 0.61% from two or more races.

There were 148 households out of which 23.0% had children under the age of 18 living with them, 50.0% were married couples living together, 8.8% had a female householder with no husband present, and 35.8% were non-families. 31.1% of all households were made up of individuals and 19.6% had someone living alone who was 65 years of age or older. The average household size was 2.21 and the average family size was 2.71.

In the city the population was spread out with 19.6% under the age of 18, 9.5% from 18 to 24, 19.3% from 25 to 44, 21.1% from 45 to 64, and 30.6% who were 65 years of age or older. The median age was 46 years. For every 100 females there were 99.4 males. For every 100 females age 18 and over, there were 92.0 males.

The median income for a household in the city was $32,917, and the median income for a family was $39,375. Males had a median income of $29,375 versus $20,625 for females. The per capita income for the city was $16,014. About 2.1% of families and 5.8% of the population were below the poverty line, including 12.1% of those under age 18 and 2.4% of those age 65 or over.