Boaz, Wisconsin

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Boaz is a village in Richland County, Wisconsin, United States. The population was 137 at the 2000 census.

[edit] Geography

Boaz is located at 43°19′51″N, 90°31′38″W (43.330793, -90.527280)^GR1.

According to the United States Census Bureau, the village has a total area of 0.9 km² (0.4 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 137 people, 64 households, and 41 families residing in the village. The population density was 146.9/km² (383.2/mi²). There were 67 housing units at an average density of 71.9/km² (187.4/mi²). The racial makeup of the village was 99.27% White and 0.73% Native American.

There were 64 households out of which 28.1% had children under the age of 18 living with them, 45.3% were married couples living together, 10.9% had a female householder with no husband present, and 35.9% were non-families. 26.6% of all households were made up of individuals and 7.8% had someone living alone who was 65 years of age or older. The average household size was 2.14 and the average family size was 2.61.

In the village the population was spread out with 21.2% under the age of 18, 10.2% from 18 to 24, 29.9% from 25 to 44, 24.1% from 45 to 64, and 14.6% who were 65 years of age or older. The median age was 40 years. For every 100 females there were 95.7 males. For every 100 females age 18 and over, there were 89.5 males.

The median income for a household in the village was $31,563, and the median income for a family was $32,000. Males had a median income of $22,500 versus $22,500 for females. The per capita income for the village was $16,883. There were 16.7% of families and 13.2% of the population living below the poverty line, including 41.7% of under eighteens and none of those over 64.