Blue Hill, Nebraska

From Wikipedia, the free encyclopedia

Blue Hill is a city in Webster County, Nebraska, United States. The population was 867 at the 2000 census.

[edit] Geography

Blue Hill is located at 40°19′52″N, 98°26′60″W (40.331008, -98.449967)^GR1.

According to the United States Census Bureau, the city has a total area of 1.9 km² (0.7 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 867 people, 350 households, and 231 families residing in the city. The population density was 452.4/km² (1,178.3/mi²). There were 392 housing units at an average density of 204.5/km² (532.8/mi²). The racial makeup of the city was 97.81% White, 0.35% African American, 0.46% Native American, 0.69% Asian, 0.46% from other races, and 0.23% from two or more races. Hispanic or Latino of any race were 0.81% of the population.

There were 350 households out of which 26.0% had children under the age of 18 living with them, 58.9% were married couples living together, 4.6% had a female householder with no husband present, and 34.0% were non-families. 32.6% of all households were made up of individuals and 20.6% had someone living alone who was 65 years of age or older. The average household size was 2.26 and the average family size was 2.85.

In the city the population was spread out with 20.8% under the age of 18, 5.2% from 18 to 24, 21.3% from 25 to 44, 22.6% from 45 to 64, and 30.1% who were 65 years of age or older. The median age was 47 years. For every 100 females there were 82.9 males. For every 100 females age 18 and over, there were 78.9 males.

The median income for a household in the city was $30,938, and the median income for a family was $43,500. Males had a median income of $29,167 versus $19,904 for females. The per capita income for the city was $15,733. About 8.1% of families and 10.4% of the population were below the poverty line, including 16.4% of those under age 18 and 11.4% of those age 65 or over.