Bloomburg, Texas

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This article is about a town in Texas. For a similarly-named town in Pennsylvania, please see Bloomsburg, Pennsylvania.

Bloomburg is a town in Cass County, Texas, United States. The population was 375 at the 2000 census.

[edit] Geography

Bloomburg is located at 33°8′19″N, 94°3′33″W (33.138602, -94.059067)^GR1.

According to the United States Census Bureau, the town has a total area of 2.6 km² (1.0 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 375 people, 155 households, and 104 families residing in the town. The population density was 143.4/km² (372.6/mi²). There were 177 housing units at an average density of 67.7/km² (175.9/mi²). The racial makeup of the town was 80.27% White, 17.60% African American, 0.80% Pacific Islander, 1.33% from other races. Hispanic or Latino of any race were 2.13% of the population.

There were 155 households out of which 29.7% had children under the age of 18 living with them, 49.0% were married couples living together, 14.8% had a female householder with no husband present, and 32.9% were non-families. 30.3% of all households were made up of individuals and 15.5% had someone living alone who was 65 years of age or older. The average household size was 2.42 and the average family size was 2.98.

In the town the population was spread out with 26.4% under the age of 18, 8.5% from 18 to 24, 24.5% from 25 to 44, 26.1% from 45 to 64, and 14.4% who were 65 years of age or older. The median age was 36 years. For every 100 females there were 78.6 males. For every 100 females age 18 and over, there were 79.2 males.

The median income for a household in the town was $27,708, and the median income for a family was $34,875. Males had a median income of $26,364 versus $30,208 for females. The per capita income for the town was $18,799. About 13.0% of families and 17.9% of the population were below the poverty line, including 18.3% of those under age 18 and 20.6% of those age 65 or over.