Barnum, Iowa

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Barnum is a city in Webster County, Iowa, United States. The population was 195 at the 2000 census.

[edit] Geography

Location of Barnum, Iowa

Barnum is located at 42°30′24″N, 94°21′52″W (42.506660, -94.364575)GR1.

According to the United States Census Bureau, the city has a total area of 0.8 km² (0.3 mi²), all land.

[edit] Demographics

As of the censusGR2 of 2000, there were 195 people, 67 households, and 51 families residing in the city. The population density was 235.3/km² (615.9/mi²). There were 70 housing units at an average density of 84.5/km² (221.1/mi²). The racial makeup of the city was 100.00% White. Hispanic or Latino of any race were 1.03% of the population.

There were 67 households out of which 58.2% had children under the age of 18 living with them, 58.2% were married couples living together, 11.9% had a female householder with no husband present, and 22.4% were non-families. 17.9% of all households were made up of individuals and 3.0% had someone living alone who was 65 years of age or older. The average household size was 2.91 and the average family size was 3.33.

In the city the population was spread out with 38.5% under the age of 18, 5.1% from 18 to 24, 35.9% from 25 to 44, 14.9% from 45 to 64, and 5.6% who were 65 years of age or older. The median age was 28 years. For every 100 females there were 103.1 males. For every 100 females age 18 and over, there were 87.5 males.

The median income for a household in the city was $40,000, and the median income for a family was $42,083. Males had a median income of $25,417 versus $20,313 for females. The per capita income for the city was $12,252. About 12.2% of families and 9.7% of the population were below the poverty line, including 12.3% of those under the age of eighteen and 57.1% of those sixty five or over.

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