Augmented matrix

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In linear algebra, the augmented matrix of a matrix is obtained by combining two matrices as shown.

If you have the matrices A and B, where

A =   \begin{bmatrix}     1 & 3 & 2 \\     2 & 0 & 1 \\     5 & 2 & 2   \end{bmatrix} B =   \begin{bmatrix}     4 \\     3 \\     1   \end{bmatrix}

Then, the augmented matrix (A|B) is written as:

\begin{bmatrix}     1 & 3 & 2 & 4 \\     2 & 0 & 1 & 3 \\     5 & 2 & 2 & 1   \end{bmatrix}

This is useful when solving systems of linear equations given by square matrices. They may also be used to find the inverse of a matrix. By reducing the matrix into row-echelon form, where the consistency (or inconsistency) of the system can be read off.

[edit] Examples

Let C be a square 2x2 matrix where C =    \begin{bmatrix}     1 & 3 \\     -5 & 0   \end{bmatrix}

To find the inverse of C we create (C|I) where I is the 2x2 identity matrix. We then reduce the part of (C|I) corresponding to C to the identity matrix using only Elementary matrix transformations on (C|I).

(C|I) =    \begin{bmatrix}     1 & 3 & 1 & 0\\     -5 & 0 & 0 & 1   \end{bmatrix}

(I|C^{-1}) =    \begin{bmatrix}     1 & 0 & 0 & -\frac{1}{5} \\     0 & 1 & \frac{1}{3} & \frac{1}{15}   \end{bmatrix}

As used in linear algebra, an augmented matrix is used to represent the coefficients as well as the constants of each equation. For the set of equations:

\begin{cases} x_1 + 2x_2 + 3x_3 = 0 \\ 3x_1 + 4x_2 + 7x_3 = 2 \\ 6x_1 + 5x_2 + 9x_3 = 11 \end{cases}

the augmented matrix would be composed of

A = \begin{bmatrix} 1 & 2 & 3 \\ 3 & 4 & 7 \\ 6 & 5 & 9 \end{bmatrix}

and

B =  \begin{bmatrix} 0 \\ 2 \\ 11 \end{bmatrix}

Leaving us with:

C = \begin{bmatrix} 1 & 2 & 3 & 0 \\ 3 & 4 & 7 & 2 \\ 6 & 5 & 9 & 11 \end{bmatrix}.

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