Arcadia, Iowa

From Wikipedia, the free encyclopedia

Arcadia is a city in Carroll County, Iowa, United States. The population was 443 at the 2000 census.

[edit] Geography

Arcadia is located at 42°5′13″N, 95°2′44″W (42.086903, -95.045594)^GR1.

According to the United States Census Bureau, the city has a total area of 2.5 km² (1.0 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 443 people, 172 households, and 125 families residing in the city. The population density was 174.5/km² (453.2/mi²). There were 183 housing units at an average density of 72.1/km² (187.2/mi²). The racial makeup of the city was 99.55% White and 0.45% Asian. Hispanic or Latino of any race were 0.23% of the population.

There were 172 households out of which 33.7% had children under the age of 18 living with them, 65.7% were married couples living together, 4.7% had a female householder with no husband present, and 27.3% were non-families. 25.6% of all households were made up of individuals and 17.4% had someone living alone who was 65 years of age or older. The average household size was 2.58 and the average family size was 3.11.

In the city the population was spread out with 27.5% under the age of 18, 8.6% from 18 to 24, 26.4% from 25 to 44, 15.8% from 45 to 64, and 21.7% who were 65 years of age or older. The median age was 38 years. For every 100 females there were 113.0 males. For every 100 females age 18 and over, there were 96.9 males.

The median income for a household in the city was $34,063, and the median income for a family was $45,278. Males had a median income of $28,636 versus $18,750 for females. The per capita income for the city was $16,584. About 2.7% of families and 6.1% of the population were below the poverty line, including 9.3% of those under age 18 and 6.2% of those age 65 or over.