Alvord, Iowa

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Alvord is a city in Lyon County, Iowa, United States. The population was 187 at the 2000 census.

[edit] Geography

Alvord is located at 43°20′32″N, 96°18′13″W (43.342324, -96.303715)^GR1.

According to the United States Census Bureau, the city has a total area of 0.7 km² (0.3 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 187 people, 75 households, and 54 families residing in the city. The population density was 267.4/km² (684.8/mi²). There were 80 housing units at an average density of 114.4/km² (292.9/mi²). The racial makeup of the city was 100.00% White.

There were 75 households out of which 33.3% had children under the age of 18 living with them, 69.3% were married couples living together, 2.7% had a female householder with no husband present, and 26.7% were non-families. 25.3% of all households were made up of individuals and 14.7% had someone living alone who was 65 years of age or older. The average household size was 2.49 and the average family size was 3.02.

In the city the population was spread out with 24.1% under the age of 18, 8.6% from 18 to 24, 27.8% from 25 to 44, 24.1% from 45 to 64, and 15.5% who were 65 years of age or older. The median age was 36 years. For every 100 females there were 94.8 males. For every 100 females age 18 and over, there were 94.5 males.

The median income for a household in the city was $38,750, and the median income for a family was $41,786. Males had a median income of $31,250 versus $20,625 for females. The per capita income for the city was $17,300. None of the families and 2.0% of the population were living below the poverty line, including no under eighteens and 16.7% of those over 64.