Alpine, Wyoming

From Wikipedia, the free encyclopedia

Alpine is a town in Lincoln County, Wyoming, United States. The population was 550 at the 2000 census.

[edit] Geography

Alpine is located at 43°9′40″N, 111°1′4″W (43.161223, -111.017883).^GR1

According to the United States Census Bureau, the town has a total area of 1.8 km² (0.7 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 550 people, 217 households, and 146 families residing in the town. The population density was 303.4/km² (787.9/mi²). There were 274 housing units at an average density of 151.1/km² (392.5/mi²). The racial makeup of the town was 96.73% White, 0.73% Native American, 0.73% Asian, 0.18% Pacific Islander, and 1.64% from two or more races. Hispanic or Latino of any race were 1.09% of the population.

There were 217 households out of which 27.6% had children under the age of 18 living with them, 61.8% were married couples living together, 5.1% had a female householder with no husband present, and 32.7% were non-families. 18.4% of all households were made up of individuals and 3.2% had someone living alone who was 65 years of age or older. The average household size was 2.53 and the average family size was 2.99.

In the town the population was spread out with 23.8% under the age of 18, 6.5% from 18 to 24, 36.7% from 25 to 44, 25.3% from 45 to 64, and 7.6% who were 65 years of age or older. The median age was 36 years. For every 100 females there were 107.5 males. For every 100 females age 18 and over, there were 97.6 males.

The median income for a household in the town was $45,313, and the median income for a family was $47,813. Males had a median income of $35,313 versus $23,036 for females. The per capita income for the town was $21,223. About 3.4% of families and 5.1% of the population were below the poverty line, including 4.1% of those under age 18 and none of those age 65 or over.