Adrian, Texas

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Adrian is a city in Oldham County, Texas, United States. The population was 159 at the 2000 census.

1 Geography
2 Demographics
3 Trivia
4 Education
5 External links

[edit] Geography

Adrian is located at 35°16′28″N, 102°39′59″W (35.274489, -102.666385)^GR1.

According to the United States Census Bureau, the city has a total area of 2.3 km² (0.9 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 159 people, 72 households, and 48 families residing in the city. The population density was 69.8/km² (179.9/mi²). There were 82 housing units at an average density of 36.0/km² (92.8/mi²). The racial makeup of the city was 82.39% White, 1.26% Native American, 16.35% from other races. Hispanic or Latino of any race were 21.38% of the population.

There were 72 households out of which 23.6% had children under the age of 18 living with them, 54.2% were married couples living together, 9.7% had a female householder with no husband present, and 33.3% were non-families. 31.9% of all households were made up of individuals and 12.5% had someone living alone who was 65 years of age or older. The average household size was 2.21 and the average family size was 2.79.

In the city the population was spread out with 21.4% under the age of 18, 6.3% from 18 to 24, 22.0% from 25 to 44, 30.2% from 45 to 64, and 20.1% who were 65 years of age or older. The median age was 46 years. For every 100 females there were 91.6 males. For every 100 females age 18 and over, there were 86.6 males.

The median income for a household in the city was $27,083, and the median income for a family was $33,750. Males had a median income of $33,333 versus $21,875 for females. The per capita income for the city was $17,966. About 13.6% of families and 24.1% of the population were below the poverty line, including 33.3% of those under the age of eighteen and 21.7% of those sixty five or over.