Yoder, Wyoming

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Yoder is a town in Goshen County, Wyoming, United States. The population was 169 at the 2000 census.

[edit] Geography

Yoder is located at 41°55′3″N, 104°17′42″W (41.917560, -104.295060)^GR1.

According to the United States Census Bureau, the town has a total area of 0.5 km² (0.2 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 169 people, 66 households, and 45 families residing in the town. The population density was 326.3/km² (829.3/mi²). There were 84 housing units at an average density of 162.2/km² (412.2/mi²). The racial makeup of the town was 93.49% White, 0.59% Native American, 2.37% Pacific Islander, 2.37% from other races, and 1.18% from two or more races. Hispanic or Latino of any race were 3.55% of the population.

There were 66 households out of which 34.8% had children under the age of 18 living with them, 57.6% were married couples living together, 6.1% had a female householder with no husband present, and 31.8% were non-families. 28.8% of all households were made up of individuals and 12.1% had someone living alone who was 65 years of age or older. The average household size was 2.56 and the average family size was 3.09.

In the town the population was spread out with 30.2% under the age of 18, 3.6% from 18 to 24, 29.6% from 25 to 44, 23.7% from 45 to 64, and 13.0% who were 65 years of age or older. The median age was 39 years. For every 100 females there were 119.5 males. For every 100 females age 18 and over, there were 110.7 males.

The median income for a household in the town was $40,781, and the median income for a family was $41,875. Males had a median income of $37,500 versus $15,000 for females. The per capita income for the town was $15,161. About 5.3% of families and 8.7% of the population were below the poverty line, including 6.3% of those under the age of eighteen and none of those sixty five or over.