Wilson, Arkansas

From Wikipedia, the free encyclopedia

Wilson is a town in Mississippi County, Arkansas, United States. The population was 939 at the 2000 census.

[edit] Geography

Wilson is located at 35°34′4″N, 90°2′37″W (35.567868, -90.043637)^GR1.

According to the United States Census Bureau, the town has a total area of 2.8 km² (1.1 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 939 people, 364 households, and 264 families residing in the town. The population density was 338.8/km² (873.9/mi²). There were 386 housing units at an average density of 139.3/km² (359.3/mi²). The racial makeup of the town was 73.27% White, 26.30% Black or African American, 0.11% Native American, 0.32% from other races. 0.96% of the population were Hispanic or Latino of any race.

There were 364 households out of which 36.8% had children under the age of 18 living with them, 48.4% were married couples living together, 19.8% had a female householder with no husband present, and 27.2% were non-families. 25.0% of all households were made up of individuals and 11.3% had someone living alone who was 65 years of age or older. The average household size was 2.58 and the average family size was 3.07.

In the town the population was spread out with 28.3% under the age of 18, 8.4% from 18 to 24, 25.5% from 25 to 44, 25.6% from 45 to 64, and 12.2% who were 65 years of age or older. The median age was 37 years. For every 100 females there were 80.9 males. For every 100 females age 18 and over, there were 79.5 males.

The median income for a household in the town was $33,625, and the median income for a family was $38,971. Males had a median income of $30,526 versus $20,625 for females. The per capita income for the town was $14,738. About 10.7% of families and 11.8% of the population were below the poverty line, including 12.1% of those under age 18 and 20.2% of those age 65 or over.