Whitestown, Indiana

From Wikipedia, the free encyclopedia

Whitestown is a town in Boone County, Indiana, United States. The population was 471 at the 2000 census.

[edit] Geography

Whitestown is located at 39°59′46″N, 86°20′41″W (39.996136, -86.344612)^GR1.

According to the United States Census Bureau, the town has a total area of 0.7 km² (0.3 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 471 people, 175 households, and 131 families residing in the town. The population density was 699.4/km² (1,843.9/mi²). There were 187 housing units at an average density of 277.7/km² (732.1/mi²). The racial makeup of the town was 99.15% White, 0.21% Asian, and 0.64% from two or more races. Hispanic or Latino of any race were 0.64% of the population.

There were 175 households out of which 40.6% had children under the age of 18 living with them, 61.7% were married couples living together, 8.0% had a female householder with no husband present, and 24.6% were non-families. 20.6% of all households were made up of individuals and 4.0% had someone living alone who was 65 years of age or older. The average household size was 2.69 and the average family size was 3.10.

In the town the population was spread out with 29.5% under the age of 18, 5.1% from 18 to 24, 37.4% from 25 to 44, 21.0% from 45 to 64, and 7.0% who were 65 years of age or older. The median age was 35 years. For every 100 females there were 103.9 males. For every 100 females age 18 and over, there were 100.0 males.

The median income for a household in the town was $46,528, and the median income for a family was $47,917. Males had a median income of $32,031 versus $25,893 for females. The per capita income for the town was $21,674. About 8.1% of families and 7.3% of the population were below the poverty line, including 13.6% of those under age 18 and none of those age 65 or over.