Wallace, Nebraska

From Wikipedia, the free encyclopedia

Wallace is a village in Lincoln County, Nebraska, United States. The population was 329 at the 2000 census.

[edit] Geography

Wallace is located at 40°50′19″N, 101°9′52″W (40.838672, -101.164365)^GR1.

According to the United States Census Bureau, the village has a total area of 1.8 km² (0.7 mi²), all land.

[edit] Demographics

As of the census^GR2 of 2000, there were 329 people, 134 households, and 97 families residing in the village. The population density was 181.5/km² (467.5/mi²). There were 145 housing units at an average density of 80.0/km² (206.0/mi²). The racial makeup of the village was 99.39% White, 0.30% Native American, 0.30% from other races. Hispanic or Latino of any race were 0.61% of the population.

There were 134 households out of which 32.8% had children under the age of 18 living with them, 64.2% were married couples living together, 3.7% had a female householder with no husband present, and 26.9% were non-families. 26.1% of all households were made up of individuals and 11.9% had someone living alone who was 65 years of age or older. The average household size was 2.46 and the average family size was 2.95.

In the village the population was spread out with 28.9% under the age of 18, 4.6% from 18 to 24, 22.2% from 25 to 44, 24.3% from 45 to 64, and 20.1% who were 65 years of age or older. The median age was 42 years. For every 100 females there were 86.9 males. For every 100 females age 18 and over, there were 98.3 males.

The median income for a household in the village was $36,771, and the median income for a family was $41,346. Males had a median income of $30,179 versus $19,688 for females. The per capita income for the village was $22,033. About 6.4% of families and 9.5% of the population were below the poverty line, including 18.3% of those under age 18 and none of those age 65 or over.